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Weaving - number of threads versus blank O.D.
Posted by:
Ron Beagles
(208.254.111.---)
Date: December 22, 2005 02:17PM
Ok guys - I have done some weaving and probably been lucky so far in that the number of threads has not gone over or around the blank od. I can use pc stitch and another version ok - I can bring in my picture, convert and set all that up. but figuring number of threads to use per the software is confusing to me.
do I eyeball it? is there some math and measurements to use? gotta know! Please - Re: Weaving - number of threads versus blank O.D.
Posted by:
Jim Upton
(---.lsanca.dsl-w.verizon.net)
Date: December 22, 2005 04:01PM
Which version of pcstitch are you using? The place to determine the number of threads in the pattern is where you can determine size and cloth count. You will find that window as you go through importing a picture. Change the size from inches to threads (eg 100) and the cloth count to half of that (50) and see how it looks in the preview window. If you have enough detail to suit you go with it. If not increase the thread count until you do. Now limit the number of colors to say 20 and see how that looks if that looses too much detail up the color count if it's still good try dropping to 10 and see what that does. Even if you want only to do a silhouette you may have to settle for enough colors to give you the detail you want and then change the colors to one as you work on the pattern. If your weaving jig has less slots than 100 you'll have to put in the number of threads available to you on the jig.
The number of design threads you will be able to get on the blank depends on your weaving jig, blank circumference and the size thread you are using for the design. Measure the blank circumference by putting a piece of tape around the blank and mark the tape. Then lay it out flat and measure it. If you want to know how many design threads will fit, wrap a piece of blank with whatever size thread you want to use for your design and see how many wraps you get in one centimeter and multiply that by the number of centimeters available in the circumference. Edited 1 time(s). Last edit at 12/22/2005 04:12PM by Jim Upton. Sorry, only registered users may post in this forum.
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